Question 1195032
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Still ambiguous... but now I can guess what the correct expression is.  Adding one more set of parentheses...:<br>
𝑦 = √((3𝑥 − 4)(3 −2𝑥)) / √(4𝑥² − 1)<br>
A square root is the 1/2 power, so the given expression is<br>
{{{y=((3x-4)(3-2x))^(1/2)/(4x^2-1)^(1/2)}}}<br>
When taking logarithms, the power comes out front as a multiplier; the log of the product is the sum of the logs; and the log of the quotient is the difference of the logs:<br>
{{{log(y)=(1/2)(log((3x-4))+log((3-2x)))-(1/2)log((4x^2-1))}}}