Question 1194937
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Hint:
This is what the diagram could look like
<img width="45%" src = "https://i.imgur.com/MiwMtSL.png">
The diagram was made with GeoGebra.


Points:<ul><li>A = top of the building</li><li>B = base of the building</li><li>C = location of the observer</li><li>D = point needed to help form a right triangle</li></ul>Further useful information:<ul><li>The red segment (AB) is 20 meters in height</li><li>Angle BCD = 37°22′ = 37+22/60 = 37.36667° (approximate)</li><li>Angle ACD = 41°27′ = 41+27/60 = 41.45° (exact)</li><li>Segment BD is the height of the hill.</li><li>Angle BCD is marked in blue.</li><li>Angle ACD is marked in purple.</li><li>The dashed line (segment BC) is the hill itself.</li></ul>Yet another hint: Break the figure into two separate right triangles ADC and BDC. 
Use trigonometry to determine x and y.
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