Question 1194906
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If *[tex \LARGE \frac{t}{j}\ =\ \frac{4}{9}]


Then *[tex \LARGE t\ =\ \frac{4j}{9}]


Then, since *[tex \LARGE t\ =\ 2(j\,-\,21)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{4j}{9}\ =\ 2(j\,-\,21)]


Solve for *[tex \LARGE j] and then substitute your value for *[tex \LARGE j] into *[tex \LARGE t\ =\ \frac{4j}{9}] and solve for *[tex \LARGE t]


You can do your own arithmetic.

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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