Question 1194872
4400*0.01=44=np units number of bulbs
the variance is np(1-p)=44*0.99=43.56 units # of bulbs^2
the sd is sqrt(43.56)=6.6 units number of bulbs
for 0.015% or 66 bulbs, an approximation would be z>(66.5-44)/6.6=3.41. I use 66.5 because of the continuity correction factor, and the number has to be greater than 66.
probability z>3.41 is 0.0003