Question 1194839
Please simplify this problem and show all the steps so I can understand how it was simplified.

<pre>{{{((3+2h)/(1+h)-3)/(2+h-2)}}} = {{{(3 + 2h)/(1 + h) - 3)}}} <font color = red><font size = 5><b>÷</font></font></b> {{{2 + h - 2}}} 
             = {{{(3 + 2h)/(1 + h) - 3/1)}}} <font color = red><font size = 5><b>÷</font></font></b> {{{h}}} 
             = {{{(3 + 2h)/(1 + h) - 3/1}}} <font color = red><font size = 5><b>*</font></font></b> {{{1/h}}} ------ Applying KCF
             = {{{(((3 + 2h) - 3(1 + h))/(1 + h)) * (1/h)}}} 
             = {{{((3 + 2h - 3 - 3h)/(1 + h)) * (1/h)}}}  
             = {{{matrix(1,5, ((- h)/(1 + h)) * (1/h), "=", ((- 1*cross(h))/(1 + h)) * (1/cross(h)), "=", highlight_green(- 1/(1 + h)))}}}