<PRE><B>Question 1194829</B>
Theodore invests a total of $39,000 in two accounts paying 12% and 7% annual interest, respectively.
let a = amt invested at 12%
the total invested is $39000, therefore:
(39000-a) = amt invested at 7%
:
 How much was invested in each account if, after one year, the total interest was $3,730.00.
.12a + .07(39000-a) = 3730
.12a + 2730 - .07a = 3730
.12a - .07a = 3730 - 2730
.05a = 1000
a = 1000/.05
a = $20,000 invested at 12%
then obviously,
39000 - 20000 = $19,000 invested at 7%
:
:
Check this, find the actual interest on each account total
.12(20000) = 2400
.07(19000) = 1330
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total int: 3730




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