Question 1194670
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Both functions are monotonically increasing -- an increase in x means an increase in y.<br>
a) A positive number raised to any real number power is valid expression; and it is always positive.  So the domain of both functions is all real numbers, and the range of both functions is y>0.<br>
b) Since both functions are monotonically increasing, they will intersect at only one point.  Since any number to the 0 power is equal to 1, the single point of intersection is (0,1).<br>
c) I will assume by "2^x+4-3" what you mean is "2^(x+4)-3" = {{{2^(x+4)-3}}}.  The "x+4" shifts the graph 4 units to the left; then the "-3" shifts it 3 units down.<br>
Here is a graph:
y=2^x (red),
y=2^(x+4) (green) (red, shifted 4 to the left),
y=2^(x+4)-3 (blue) (green, shifted 3 down)<br>
{{{graph(800,400,-6,6,-6,16,2^x,2^(x+4),2^(x+4)-3)}}}<br>
d) {{{(1/2)^x = (2^(-1))^x = 2^(-x)}}}<br>
That means the graph of y=(1/2)x is the reflection in the y axis of y=2^x.<br>
Here is a graph:
y=2^x (red);
y=(1/2)^x=2^(-x) (green)<br>
{{{graph(400,400,-4,4,-2,18,2^x,(1/2)^x)}}}<br>