Question 1194662

The width of a rectangle is 15 less than twice its length. If the perimeter of the rectangle is 30 feet, what are the dimensions?
<pre>With L being length, width = 2L - 15
{{{matrix(5,3, 2(Length + Width), "=", Perimeter, 2(L + 2L - 15), "=", 30, L + 2L - 15, "=", 30/2, 3L - 15, "=", 15, 3L, "=", 30)}}}
     Length or {{{highlight_green(matrix(1,6, L, "=", 30/3, "=", 10, feet))}}} 
You should now be able to find width, and you'll then have the dimensions (length & width).