Question 1194662


The width of a rectangle {{{W}}} is {{{15}}} less than twice its length {{{L}}}.

{{{W=2L-15ft}}}

 If the perimeter of the rectangle is {{{30}}} feet, we have

{{{2(L+W)=30ft}}}...substitute {{{W}}}

{{{2(L+2L-15ft)=30ft}}}

{{{L+2L-15ft=15ft}}}

{{{3L=15ft+15ft}}}

{{{3L=30ft}}}

{{{L=10ft}}}

no find the width


{{{W=2*10ft-15ft}}}

{{{W=20ft-15ft}}}

{{{W=5ft}}}


so,  the dimensions are:

length is {{{10ft}}}

width is {{{5ft}}}