Question 1194660
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{{{(4^(1/2))(8^(1/3))(64^(1/3))}}}<br>
{{{4 = 2^2}}}; {{{4^(1/2)=(2^2)(1/2)=2^(2(1/2))=2^1}}}
{{{8=2^3}}}; {{{8^(1/3)=(2^3)^(1/3)=2^(3(1/3))=2^1}}}
{{{64=2^6}}}; {{{64^(1/3)=(2^6)^(1/3)=2^(6(1/3))=2^2}}}<br>
{{{(4^(1/2))(8^(1/3))(64^(1/3))=(2^1)(2^1)(2^2)=2^(1+1+2)=2^4}}}<br>
ANSWER: a. 2^4<br>
In your second problem, I don't know what "y 2" in the statement of the problem means, nor do I know what "2 2x" and "2 4x" means in answer choices a and d.<br>
If it means y squared, then use the standard notation "y^2"; if it means y^2, then the answer is (2x)^2 = 4x^2, which is none of the answer choices.<br>