Question 1194342
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There are infinitely many solutions, here's one, approximately:

a=0.5, x=0.03125, y=0.642286

{{{log(0.5,0.03125) = ln(0.03125)/ln(0.5) = 5}}}

{{{0.641186 = log(0.5,0.641186) = ln(0.641186)/ln(0.5) = 0.6411851696 }}}, approximately

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here's another, approximately:

a=1.2, x=2.48832, y=1.25773

{{{log(1.2,2.48832) = ln(2.48832)/ln(1.2) = 5}}}

{{{1.25773 = log(1.2,1.25773) = ln(1.25773)/ln(1.2) = 1.257714737 }}}, approximately.

Edwin<pre>