Question 1194295
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If repetition of the digits is allowed in the code,  (which you may assume,  since the problem 
does not prohibit it),  then in each of the  6  positions there are  10  possible digits from  0  to  9,  inclusive.


In &nbsp;6 &nbsp;positions, &nbsp;it gives  &nbsp;&nbsp;{{{10^6}}} = 1,000,000 &nbsp;&nbsp;possible codes &nbsp;(one million), &nbsp;in total.     &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<U>ANSWER</U>


Solved and explained.