Question 1194243
you need point slope formula:

{{{y-y[1]=m(x-x[1])}}}

the equation of the line that has slope {{{m=2/3}}}, passing through the point ({{{0}}}, {{{-5}}}) is:


{{{y-y[1]=m(x-x[1])}}}...substitute given data

{{{y-(-5)=(2/3)(x-0)}}}

{{{y+5=(2/3)x}}}

{{{y=(2/3)x-5}}}-> your equation


{{{ drawing( 600, 600, -10, 10, -10, 10,
circle(0,-5,.12), locate(0.3,-5,p(0,-5)),
graph( 600, 600, -10, 10, -10, 10, (2/3)x-5)) }}}