Question 1194141
The product of two consecutive odd integers is 1 less than 5 times their sum. 
Find the two integers.
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n*(n+2) + 1 = 5(n + n+2)
n^2 + 2n + 1 = 10n + 10
n^2 - 8n - 9 = 0
(n-9)*(n+1) = 0
n = 9
---> n & 11
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n = -1 
---> -1 & +1