Question 1194141
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The product of two consecutive odd integers is 
1
 less than 
5
 times their sum. Find the two integers. Answer in the form of paired points with the lowest of the two integers first.
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The product of two consecutive odd integers is 1 less than 
5 times their sum. Find the two integers. 
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Integers n and n+2

{{{n(n+2)=-1+5(n+(n+2))}}}

{{{n^2+2n=-1+5(2n+2)}}}

{{{n^2+2n=10n+10-1}}}

{{{n^2=8n+9}}}

{{{n^2-8n-9=0}}}

{{{(n-9)(n+1)=0}}}

{{{system(n=-1,or,n=9)}}}-----------and you can now find the two possible pair of integers.