Question 113147
7x to the 5th power y to the 5th power - 21x to the 4th power y to the 4th power + 14x to the 3rd power y to the 3rd power OVER 7x to the 3rd power y to the 3rd power
:
We can write it:
{{{(7x^5y^5-21x^4y^4+14x^3y^3)/(7x^3y^3)}}}
:
Note that in the numerator we can factor out {{{7x^3y^3}}}:
{{{(7x^3y^3(x^2y^2-3xy+2))/(7x^3y^3)}}}
:
Note that the {{{(7x^3y^3)}}}'s conveniently cancel and we have
:
{{{(x^2y^2-3xy+2)}}}
:
But that is an expression that will factor also:
(xy - 2)(xy - 1)