Question 1194076
<br>
(i) ANSWER: 3x+5y=150<br>
x and y are non-negative integers.<br>
Since 5y is a multiple of 5 and the total 150 is a multiple of 5, 3x must also be a multiple of 5; and that means s must be a multiple of 5.<br>
(ii) If 2 units of B are manufactured each day, then y=2, and<br>
3x+10=150
3x=140<br>
But 140 is not a multiple of 3 -- so 2 units of B manufactured each day violates the requirement that all 150 labor hours be used.<br>
ANSWER: There is no solution to this problem<br>
(iii) This problem talks about production in a week, assuming a 5-day work week.  But we have the same problem here as in (ii) -- if y=25 then daily production is<br>
3x+125=150
3x=25<br>
And again 25 is not a multiple of 3, so the requirement of using all 150 labor hours can't be met.<br>
ANSWER: Again there is no solution to this problem.<br>