Question 1194008


subtract {{{(6y^2-4y-2)}}} from the {{{sum}}} of {{{(2y^2+2)}}} and {{{(4y+7)}}}


first find the {{{sum }}}of {{{(2y^2+2) and (4y+7)}}}

 {{{(2y^2+2) + (4y+7)=2y^2+2+ 4y+7=2y^2+ 4y+9}}}


now subtract {{{(6y^2-4y-2)}}} from {{{2y^2+ 4y+9}}}


{{{2y^2+ 4y+9-(6y^2-4y-2)}}}

={{{2y^2+ 4y+9-6y^2+4y+2}}}

={{{-4y^2+ 8y+11}}}