<PRE><B>Question 1193996</B>
&lt;pre&gt;
2 defective
4 good
--
6 total

P(1st is defective) = 2/6

This leaves a total population of 5 from which the 2nd chip is selected:
P(2nd is not defective) = 4/5

P = (2/6)*(4/5) = 8/30 or approx. 0.267

</PRE>