<PRE><B>Question 1193974</B>
&lt;br&gt;
The solution from tutor @ikleyn is a typical formal algebraic solution; you should understand it and know how to do it.&lt;br&gt;
But a bit of logical reasoning gives us an easier way to solve the problem.&lt;br&gt;
If the amounts of interest from the investments at 12% and 11% are equal, then the amounts invested in the two accounts must be in the ratio 11:12.  So&lt;br&gt;
11x = amount invested at 12%
12x = amount invested at 11%&lt;br&gt;
The total amount invested was $69,000:&lt;br&gt;
11x+12x=69000
23x=69000
x=3000&lt;br&gt;
ANSWER: The amounts of interest are equal if 11x=$33,000 is invested at 12% and 12x=$36,000 is invested at 11%.&lt;br&gt;
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