Question 1193961
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An exponential function is one of the form {{{y=ab^x}}}.<br>
Given two ordered (x,y) pairs that satisfy the equation, the standard path to the solution starts with plugging each set of x and y values in the general form to get two equations in the parameters a and b.  For this example...<br>
{{{6=ab^(-2)}}}
{{{1=ab^3}}}<br>
Then dividing one equation by the other eliminates parameter a, allowing you to solve for b:<br>
{{{1/6=b^5}}}
{{{b=6^(1/5)}}}<br>
Then you can plug this value of b into either original equation to solve for a.<br>
I'll let you do the work.  Since the value of b is the 5th root of 6, use a calculator....<br>