Question 1193947
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if an angle θ is a principal angle that lies in the quadrant 3 such that 0 degrees ≤ θ ≤ 360 degrees, 
determine the exact value of x, y and r for tan θ= 2/3 and draw the diagram

I got for x=3 y=2 and r= square root of 13 not sure how to draw it though
Thanks
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<pre>
{{{tan(theta)}}} = {{{y/x}}} = {{{2/3}}}.


So, if the angle  {{{theta}}}  is in Quadrant I, then you can take x = 3, y = 2.


But since the angle  {{{theta}}}  is in Quadrant III  ( ! given !),  you must take x= -3 and y= -2.


So, your point is, actually,  (x,y) = (-3,-2).


Thus, from the origin, you should move 3 units left to get x= -3, and then move 2 units down to get y= -2.


This point will be that you should mark on coordinate plane.


Do as instructed, and you will get your sough point.
</pre>

Solved, explained and completed.