Question 1193910

Christian is twice as old as Taskie while Dark is 24 years younger than Christian. If half of Christian's age is six years ago was three less than one-half the sum of Taskie's age in four years and Dark's present age, how old are these three boys? 
<pre>Let Taskie's age be T
Then Christian's is 2T, and Dark's is 2T - 24
We then get: {{{matrix(4,3, (1/2)(2T - 6), "=", (1/2)(T + 4 + 2T - 24) - 3, T - 3, "=", (1/2)(3T - 20) - 3, T, "=", (1/2)(3T - 20) - 3 + 3, T, "=", (3T - 20)/2)}}}
                      2T = 3T - 20 ------ Cross-multiplying
                 2T - 3T = - 20
                     - T = - 20
     Taskie's age, or {{{highlight_green(matrix(1,5, T, "=", (- 20)/(- 1), "=", 20))}}}
  
  Christian's age: 2(20) = 40
  Dark's age: 2(20) - 24 = 40 - 24 = 16</pre>