Question 1193619
Given:	right △DEF with 
m∠E = 2 · m∠F and EF = 14radical 3
Find:	DE and DF
△D E F is given. ∠D is a right angle.
simplest radical form	DE	=	
approximation	DE	=	
simplest radical form	DF	=	
approximation	DF	=	
<pre>AGAIN, 2 scenarios exist. 
1) &#8737s E, D, and F can be 90<sup>o</sup>, 45<sup>o</sup>, and 45<sup>o</sup>, respectively.
2) &#8737s E, D, and F can ALSO be 60<sup>o</sup>, 90<sup>o</sup>, and 30<sup>o</sup>, respectively.
This triangle can therefore be a 45-45-90 special triangle, or one of the 30-60-90 variety, since DE and DF can EACH have 2 different lengths.