Question 1193895
.
A theater group made appearances in two cities. 
The hotel charge before tax in the second city was $1000 lower than in the first. 
The tax in the first city was 4%, and the tax in the second city was 9%.
The total hotel tax paid for the two cities was $397.50
How much was the hotel charge in each city before tax?
~~~~~~~~~~~~~~~~~~


<pre>
x = how much the hotel charges in the first city before tax;

y = how much the hotel charges in the second city before tax.


From the problem, you have these two equations for unknown x and y

        x -     y = 1000       dollars

    0.04x + 0.09y = 397.50     dollars


From first equation, express  x = y + 1000  and substitute to the second equation. You will get

    0.04*(y+1000) + 0.09y = 397.50


Simplify and find y

    0.04y + 40 + 0.09y = 397.50

            0.13y      = 397.50 - 40

                y      = {{{357.50/0.13}}} = 2750.


<U>ANSWER</U>.  2750+1000 = 3750 dollars in the first city and 2750 dollars in the second city.
</pre>

Solved.



//////////////



The problem was copied/pasted from the screen;  therefore, its formatting was really bad and unpleasant to see.


Please do not make your job this way: RESPECT the tutors (and respect yourself).