Question 113469
In order to find the midpoint between the points (-8,-3) and (1,6), we need to average each corresponding coordinate. In other words, we need to add up the corresponding coordinates and divide the sum by 2.



So lets find the averages between the two points




To find *[Tex \Large  \textrm{x_{mid}}], average the x-coordinates between the two points

{{{x[mid]=(-8+1)/2=(-7)/2=-3.5}}}



So the x-coordinate of the midpoint is -3.5 (i.e. x=-3.5)

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To find *[Tex \Large  \textrm{y_{mid}}], average the y-coordinates between the two points

{{{y[mid]=(-3+6)/2=(3)/2=1.5}}}



So the y-coordinate of the midpoint is 1.5 (i.e. y=1.5)

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Answer:

Since the coordinates of the midpoint are x=-3.5, y=1.5, this means the midpoint is (-3.5,1.5)


Check:

Here is a graph to visually see the answer

{{{drawing(500, 500, -10, 3, -5, 8,
graph(500, 500, -10, 3, -5, 8,0),
blue(line(-8,-3,1,6)),
circle(-8,-3,0.05),
circle(-8,-3,0.08),
circle(1,6,0.05),
circle(1,6,0.08),
circle(-3.5,1.5,0.05),
circle(-3.5,1.5,0.08)

)}}} Graph of the line segment with the endpoints (-8,-3) and (1,6) with the midpoint (-3.5,1.5)




We could visually verify our answer if we simply draw right triangles from each point like this:

{{{drawing(500, 500, -10, 3, -5, 8,
graph(500, 500, -10, 3, -5, 8,0),
blue(line(-8,-3,1,6)),

line(-8,-3,-8,(-3+6)/2),
line(-8,(-3+6)/2,-3.5,1.5),
line(-3.5,1.5,(-8+1)/2,6),
line((-8+1)/2,6,1,6),

circle(-8,-3,0.05),
circle(-8,-3,0.08),
circle(1,6,0.05),
circle(1,6,0.08),
circle(-3.5,1.5,0.05),
circle(-3.5,1.5,0.08)

)}}}


Here we can see that the two triangles are congruent (they both have a right angle and equal leg lengths), so our answer is verified.