Question 1193835
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Assuming that order doesn't matter, we have 10 C 4 = 210 ways to form the team. 
I used the nCr formula as shown in the scratch work below.


n C r = (n!)/(r!(n-r)!)
10 C 4 = (10!)/(4!*(10-4)!)
10 C 4 = (10!)/(4!*6!)
10 C 4 = (10*9*8*7*6!)/(4!*6!)
10 C 4 = (10*9*8*7)/(4!)
10 C 4 = (10*9*8*7)/(4*3*2*1)
10 C 4 = (5040)/(24)
10 C 4 = 210


Notice on the third to last step, I have 10*9*8*7 over top 4*3*2*1
The numerator represents the number of permutations (where order matters) when choosing four people from a pool of ten.
We divide over 4! = 4*3*2*1 = 24 because this is the number of ways to arrange any group of four people. This leads us to the correct count of 210. This is to avoid overcounting. 



Answer: 210
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