Question 113499
{{{2*ln(x)-ln(y)+3*ln(z)}}}


First rule to apply is that {{{a*ln(x)=ln(x^a)}}}, so we can write:


{{{ln(x^2)+ln(y^(-1))+ln(z^3)}}}
{{{ln(x^2)+ln(1/y)+ln(z^3)}}}


The next rule is that the log of the product is the sum of the logs of the factors, like this:


{{{ln(abc)=ln(a)+ln(b)+ln(c)}}}.  So for this problem:


{{{ln(x^2)+ln(1/y)+ln(z^3)=ln(x^2z^3/y)}}}


Hope this helps,
John


P.S.  Next time use the asterisk '*' (Shift-8) to make the multiplication sign as in 2 * 3 = 6