Question 1193761
<font color=black size=3>
Problem 1


I'm assuming the four sides of the tetrahedral dice are labeled 1,2,3,4
There are two ways to sum to 5 and they are:
1+4 = 5
4+1 = 5


This is out of 4*4 = 16 ways to throw the two four-sided dice.


So 2/16 = 1/8 is the probability we want.


Answer: 1/8


=============================================================

Problem 2


Here are the ways to get a difference of 1, where the first die is larger than the second and I'm subtracting in the format first-second
4-3 = 1
3-2 = 1
2-1 = 1


Now let's assume that the second die is the larger of the pair and we subtract using absolute value so we get a positive result
|3-4| = 1
|2-3| = 1
|1-2| = 1
again I'm subtracting in the format first-second, but the absolute value bars ensure the result is never negative.


We have 6 such ways to get the two dice to be separated by 1. This is out of the 4*4 = 16 ways to throw the two dice.


6/16 = 3/8


Answer: 3/8



=============================================================

Problem 3


Here are all of the ways the two dice could multiply to 4
1*4 = 4
2*2 = 4
4*1 = 4
There are 3 ways to get what we want out of 16 ways to throw the dice.


Answer: 3/16
</font>