Question 1193724
<font face="Times New Roman" size="+2">


With only the data provided, she <b><i>cannot</i></b> prove that she is in the top 20% of the class.  In order to be in the top 20% of the class, she would have to be one of the top eight out of the 40 students -- *[tex \Large \frac{8}{40}\ =\ 0.20]. This is only possible if she was the <b><i>ONLY</i></b> student in the 70-79 range who scored 79.  If only one other student in that range scored 79 also, then she could only prove that she was in the top 22.5% of the class.  The data does not specify how many of the six students in the 70-79 range scored 79; it could have been all six.  Her only other option to prove the top 20% claim would be to somehow demonstrate that she was superior in some way to any other student who scored exactly 79.


																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
I > Ø
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
</font>