Question 1193725
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The space of events is the set of all pairs of the form (a,L), where "a" is an integer number from 1 to 6 and "L" is a letter H or T.


The number "a" represents the outcome of thrown the die, while the letter L represents the outcome of tossing coin.


So, the space of events has 6*2 = 12 elements with the probability of  {{{1/12}}}  each.


Thus, in case (a)  the probability is  P = {{{1/12}}}.


In case (b), the probability is 0 (zero), since the outcome "7" is impossible.


In case (c), the answer is  {{{(1/2)*(3/6)}}} = {{{(1/2)*(1/2)}}} = {{{1/4}}}.
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Solved.