Question 1193692
 find three-digit numbers
100a + 10b + c
 such that its digits are reversed when 99 is added
100a + 10b + c + 99 = 100c + 10b + a
combine like terms on the left
100a - a + 10b - 10b + c - 100c + 99 = 0
99a + 0 - 99c + 99 = 0
simplify, divide by 99
a - c - 1 - 0
a =  c + 1
obviously there are alot of numbers like this
102/201, 203/302, 304/403, 435/534, 869/968 are just a few