Question 1193681
The length of the line is sqrt(difference in x s^2+ diff In y^2)=sqrt(6.25+25)=sqrt(31.25), so one-fifth of that added to sqrt(35), and the answer squared equals 45. That is going to be the sum of what is under the radical.

the equation of the line is y-y1=m(x-x1), m slope, and (x1, y1) a point.
the slope is -5/-2.5 or 2
y+2=2(x+3)
y=2x+4
graph the line
{{{graph(300,300,-5,5,-5,5,2x+4)}}}

The line is extended downward (closest to point A)
the distance is twice as much y as x
so the sqrt of( (5+2x)^2+(2.5+x)^2)=sqrt 45
so 25+20x+4x^2+6.25+5x+x^2=45
5x^2+25x-13.75=0
x^2+5x-2.75=0 or 4x^2+20x-11=0
(2x-1)(2x+11)=0
x=1/2, -5.5
Use the positive value. The other value would be the answer on the other end
The new end point is (-3.5, -3)  and the new distance is sqrt(45), which is 1.2 * sqrt(31.25)