Question 1193671
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Presuming angle D is the right angle and E is the 60° angle, then FE is the hypotenuse.  The short leg of a 30-60-90 triangle is *[tex \Large \frac{1}{2}] times the measure of the hypotenuse and the long leg is *[tex \Large \frac{\sqrt{3}}{2}] times the measure of the hypotenuse.

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
I > Ø
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
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