Question 1193627
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Use the figure shown by one of the tutors to solve the problem without the complicated trigonometry and decimal approximations shown in the response from the other tutor.<br>
When altitude CD is drawn, triangle BCD is a 30-60-90 right triangle with hypotenuse BC=14; that makes CD=7 and BD=7*sqrt(3).<br>
And triangle ACD is a 45-45-90 right triangle with CD=7, so AD=7 also.<br>
And then AB = AD+DB = 7+7*sqrt(3).<br>