Question 1193648
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Ignore the fact that a 30% or 55% salt solution is not physically possible.  This is a math problem for giving the student practice in solving mixture problems.<br>
The formal algebraic solution provided by the other tutor uses a good traditional method.<br>
Here is a quick informal way to solve any 2-part mixture problem like this.<br>
Think of this as starting with a 55% solution and adding a 0% solution to obtain a 30% solution.  The percentage of the mixture starts at 55% and moves towards 0%, stopping when it reaches 30%.<br>
30% is 5/11 of the way from 55% to 0%.  (55 to 0 is a change of 55; 55 to 30 is a change of 25; 25/55 = 5/11.)<br>
That means 5/11 of the mixture is the 0% solution (water) that she is adding.<br>
So the amount of water to be added to make 220 ounces of the mixture is 5/11 of 220 ounces, which is 100 ounces.  So then the number of ounces of 55% solution she needs is 220-100 = 120.<br>
ANSWER: 120 ounces of the 55% solution; 100 ounces of water.<br>