Question 1193648
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x = amount of the 55% salt solution, in ounces


It isn't clear if your teacher is referring to dry ounces or fluid ounces. Though the math will lead to the same result either way.


If we had x ounces of the 55% salt solution (i.e. 55% salt, the rest water), then we have 0.55x ounces of pure salt.


We aim to have 220 ounces of total mixture, after adding in the water to dilute things. We want to dilute to a 30% salt concentration.


So,
(amount of pure salt)/(total mix) = salt concentration
(0.55x)/(220) = 0.30


Multiply both sides by 220, then divide both sides by 0.55 as the steps show below
(0.55x)/(220) = 0.30
0.55x = 220*0.30
0.55x = 66
x = 66/0.55
x = 120
We need 120 ounces of the 55% salt solution
This leaves 220-x = 220-120 = 100 ounces of pure water


Answers:
<font color=red>Water = 100 ounces</font>
<font color=red>Salt solution = 120 ounces</font>
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