Question 1193642
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The mass of the Mercury is the product of the bore volume by the density "d" of Mercury

    3.247 = {{{pi*r^2*h*d}}},

or

    3.247 = {{{3.14*r^2*2.375*13.6}}},

where 2.375 is the length of  23.75 mm, converted to centimeters.


From the formula,


    {{{r^2}}} = {{{3.247/(3.14*2.375*13.6)}}} = 0.032015,


     r = {{{sqrt(0.032015)}}} = 0.1789 cm = 1.789 mm.    


<U>ANSWER</U>. The diameter of the bore is  2r = 2*1.789 mm = 3.578 mm.
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Solved.