Question 1193629
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Picture the regular hexagon as being composed of 6 congruent equilateral triangles.<br>
Then consider triangle CBF. Angle C is 60 degrees; angle F is half of 60 degrees, or 30 degrees.<br>
So triangle CBF is a 30-60-90 right triangle, with short leg BC of length x.<br>
That makes BF (the long leg) x*sqrt(3) and CF (the hypotenuse) 2x.<br>
ANSWERS: BF = x*sqrt(3) cm; CF = 2x cm.<br>