Question 1193601
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In right △ABC with right ∠C, 
AB = 20  and  BC = 16.
Find the length of MB, if M is the midpoint of AC.
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<pre>
Your first step is to use Pythagoras to find the leg AC

    AC = {{{sqrt(20^2-16^2)}}} = {{{sqrt(400-256)}}} = {{{sqrt(144)}}} = 12.



Your next step is to divide  12  by  2  to find the length CM :  CM = 12/2 = 6.



You final step is to find MB using Pythagoras again

    MB = {{{sqrt(16^2 + 6^2)}}} = {{{sqrt(256+36)}}} = {{{sqrt(292)}}} = {{{2*sqrt(73)}}} = 17.088  units (approximately).    <U>ANSWER</U>
</pre>

Solved.



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