Question 1193497
In order to make this make sense, change c to x
:
Car A left town X for Town Y at 6:00am and travelled at an average speed of 80km/h.
 At 7.30am car B left town X for town Y.
 If car B travels at an average speed of 100km/h, at what time will it catch car A.
:
let t = travel time of car A
Car B left 1.5 hrs later, therefore
(t-1.5) = travel time of car B
:
Write a dist equation, when Car B catches Car A, they will have traveled the same distance
dist = speed * time
B's dist = A's dist
100(t-1.5) = 80t
100t - 150 = 80t
100t - 80t = 150
20t = 150
t = 150/20
t = 7.5 hrs (7 hrs 30 min)
Find the actual time 
6:00 + 7:30 = 13:30 which is 1:30 Pm 
:
:
Check this, find the actual dist each traveled
6*100 = 600 km
7.5*80 = 600 km