Question 1193413
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Peter has been saving his loose change for several days. 
When he counted his quarters and dimes, he found they had a total value $15.80. 
The number of quarters was nineteen more than three times the number of dimes. 
How many quarters and how many dimes did Peter have?
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<U>ANSWER</U>.  13 dimes and 58 quarters.



<U>Solution</U>


<pre>
x dimes and 19+3x quarters.


Write the money equation

    10x + 25*(19+3x) = 1580  cents.


Simplify and find x

    10x + 25*19 + 75x = 1580

    10x         + 75x = 1580 - 25*19

           85x        =   1105

             x        =   1105/85 

             x        =   13.  


So, there 13 dimes and 19 + 3*13 = 58 quarters.


<U>CHECK</U>.    13*10 + 58*25 = 1580  cents,  total.    ! correct !
</pre>

Solved.