<PRE><B>Question 1192862</B>
error for conservative 0.5 estimate=z(0.995)*sqrt(0.5*0.5/n)
square both sides
0.0009=6.636*0.25/n
n=6.636*0.25/0.0009=1843.27 or 1944.
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second one 0.03=2.576*.sqrt(0.0969/n)
0.0009=6.635*0.0969/n
n=713.29 or 714.

Really want to make a difference, use less confidence and allow the error to get a little larger...</PRE>