Question 1193393
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Here is another strategy for solving a problem like this that you won't find in you standard algebra textbooks.<br>
Since the sum of the two numbers is 32, let the two numbers be 16+x and 16-x.  Then, since the product is 240,<br>
{{{(16+x)(16-x)=240}}}
{{{256-x^2=240}}}
{{{x^2=16}}}
{{{x=4}}}<br>
ANSWER: The two numbers are 16+4 = 20 and 16-4 = 12<br>