Question 1193387
The period P (in seconds) of a pendulum is given by a function P=2π √(L/32), where L is the pendulum length (in feet). 
A pendulum has a period of 4 seconds. 
Is this pendulum twice as long as a pendulum with period of 2 seconds?
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From the given formula, the length of the pendulum in feet is

    L = {{{32*(P/(2*pi))^2}}}.



If the period P is 4 seconds, then the length of the pendulum is

    L(4) = {{{32*(4/(2*3.14))^2}}} = 12.98 feet (approximately).



If the period P is 2 seconds, then the length of the pendulum is

    L(2) = {{{32*(2/(2*3.14))^2}}} = 3.25 feet (approximately).



Is the length L(4) twice as long as the length L(2) ?  - No.   The length L(4) is four times the length L(2).    <U>ANSWER</U>
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Solved.