Question 1193363
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<pre>

In the given number 348838, there are 6 digits;


of them, digit "3" has multiplicity 2 and digit "8" has multiplicity 3.


Therefore, the number of distinguishable permutations is  {{{6!/(2!*3!)}}} = {{{720/(2*6)}}} = 60.    <U>ANSWER</U>
</pre>

Solved.



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<U>NOTICE</U>: &nbsp;&nbsp;In this problem, &nbsp;there is only one given number; 


therefore, &nbsp;grammatically and logically correct is to use single &nbsp;" number " &nbsp;instead of plural &nbsp;" numbers ".