Question 1193323
probability of each breakdown from 0 to 3 is e^-lambda*lambda^x/x!
so p(0)=e^-3.2=0.0408
p(1)=).0408*3.2^1=0.1304 (round at end)
p(2)=0.0408*3.2^2/2!=0.2089
p(3)=0.0408*3.2^3/6=0.2228
the answer is 1-that sum=0.3971 (0.3975 with a calculator with rounding at the end). Find out where the intermediate steps should be rounded.