Question 1193307
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The other tutor showed a solution using a method that you would likely see in a typical algebra textbook.<br>
Here is another method that can be used that often makes the work required to solve the problem easier.<br>
The perimeter is 40, so the average side length is 40/4=10. So<br>
let 10+x = length
let 10-x = width<br>
The area is 96:<br>
{{{(10+x)(10-x)=96}}}
{{{100-x^2=96}}}
{{{x^2=4}}}
{{{x=2}}}<br>
ANSWER: The length is 10+x=12; the width is 10-x=8<br>