Question 113447
Let x be the amt. each started with.
The loser lost x/4+50.
Combined holdings always total 2x.
x-(x/4+50)+2(x-(x/4+50))=2x
x-x/4-50+2(x-x/4-50)=2x
x-x/4-50+2x-2x/4-100=2x
4x-x-200+8x-2x+-400=8x multiply each side by 4 to eliminate fractions.
9x-600=8x
x=$600 what they each started with.
Loser had 600-(600/4+50)
=600-(150+50)
=600-200=$400.
The winner had 2*400=$800.
Ed