Question 1193244
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You get to roll a standard die one time. If you roll an odd number, you win $3. 
If you roll a 4, you win $5. If you roll any other number, you lose $9.
Find the expected value for this game.
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The expected value of this game is

    E = {{{(1/6)*3 + (1/6)*5 - (1/6)*9 - (1/6)*9 - (1/6)*9 - (1/6)*9}}} = {{{(3 + 5 - 4*9)/6}}} = {{{-28/6}}} = - 4 {{{2/3}}}.


It means that playing this game many times, the player loses 4.67 dollars per game, in average.
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Solved, answered and explained.